Host:     pg.pg4e.com 

Port:     5432 

Database: pg4e_9a5114db37 

User:     pg4e_9a5114db37 

Password:  (hide/show copy) 

​

​

psql -h pg.pg4e.com -p 5432 -U pg4e_9a5114db37 pg4e_9a5114db37

const numbers = [1, 2, 3, 4, 5];

​

for (i = 0; i < numbers.length; i++) {

  console.log(numbers[i]);

} 

/* new options with IE6: loop through array of objects */

​

const people = [

  {id: 100, name: 'Vikash'},

  {id: 101, name: 'Sugam'},

  {id: 102, name: 'Ashish'}

];

​

// using for of

for (let persone of people) {

  console.log(persone.id + ': ' + persone.name);

}

​

// using forEach(...)

people.forEach(person => {

 console.log(persone.id + ': ' + persone.name);

});

// output of above two methods

// 100: Vikash

// 101: Sugam

// 102: Ashish

​

​

// forEach(...) with index

people.forEach((person, index) => {

 console.log(index + ': ' + persone.name);

});

// output of above code in console

// 0: Vikash

// 1: Sugam

// 2: Ashish

var arr = [1, 2, 3, 4, 5];

for (var i = arr.length - 1; i >= 0; i--) {

    console.log(arr[i]);

}

var min = arr[0];

var max = arr[0];

​

for(var i=1; i<arr.length; i++){

    if(arr[i] < min){

        min = arr[i];

}

    if(arr[i] > max){

        max = arr[i];

}

​

​

return [min, max];

}

let arr = [1, 2, 3, 4]

for (let i = 0; i < arr.length; i++) {

console.log(arr[i])

}

array.map((e)=>{

return(<h1>e.objectfieldName</h1>)

})

var arr = ['a', 'b', 'c'];

​

arr.forEach(item => {

    console.log(item);

});

You may assume that the sequence is always correct, i.e., every booked room was previously free, and every freed room was previously booked.

​

In case, 2 rooms have been booked the same number of times, you have to return Lexographically smaller room.

​

A string 'a' is lexicographically smaller than a string 'b' (of the same length) if in the first position where 'a' and 'b' differ, string 'a' has a letter that appears earlier in the alphabet than the corresponding letter in string 'b'. For example, "abcd" is lexicographically smaller than "acbd" because the first position they differ in is at the second letter, and 'b' comes before 'c'.

​

array.forEach(el => {

    console.log(el);

})

var temp = [];

​

for(var i=0; i<arr1.length; i++){

    temp.push(arr1[i]);

}

​

for(var i=0; i<arr2.length; i++){

    temp.push(arr2[i]);

}

console.log('temp is now', temp);

return temp;

}