Two Integer Sum II

kouqhar answered on October 29, 2024 Popularity 1/10 Helpfulness 1/10

answer Two Integer Sum II

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Two Integer Sum II

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/*

  Given an array of integers numbers that is sorted in non-decreasing order.

  Return the indices (1-indexed) of two numbers, [index1, index2], such that 
  they add up to a given target number target and index1 < index2. Note that 
  index1 and index2 cannot be equal, therefore you may not use the same 
  element twice.

  There will always be exactly one valid solution.
  Your solution must use O(1) additional space.

  Example 1:
  Input: numbers = [1,2,3,4], target = 3
  Output: [1,2]
  
  Explanation:
  The sum of 1 and 2 is 3. Since we are assuming a 1-indexed array, 
  index1 = 1, index2 = 2. We return [1, 2].
  
*/

  			/* Method One */
  
  const twoSum = (numbers, target) => {
    for(let j=0; j<numbers.length; j++){
      for(let i=j + 1; i<numbers.length; i++){
        const [currentNumber, nextNumber] = [numbers[j], numbers[i]]

        if(nextNumber == undefined) break
        else{
          if(currentNumber === nextNumber) continue

          const sum = (currentNumber) + (nextNumber)
          if(sum === target) return [j + 1, i + 1]
        }
      }
    }
  }
  
  			/* Method Two */
  
  const twoSum = (numbers, target) => {
        let l = 0, r = numbers.length - 1;

        while (l < r) {
            const curSum = numbers[l] + numbers[r];

            if (curSum > target) r--;
           	else if (curSum < target) l++;
            else return [l + 1, r + 1];
        }
    
        return [];
    }
  
  const numbers = [-1,0]
  const target = -1
  const result = twoSum(numbers, target)
  
  console.log(result)

// With love @kouqhar

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Tags: integer javascript sum

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Contributed on Oct 29 2024

kouqhar

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Contributed on Oct 29 2024

Yubraj Koirala

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Two Integer Sum II

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