# Python 3 code to demonstrate

# to remove elements present in other list

# using list comprehension

# Initializing list

test_list = [1, 3, 4, 6, 7]

# Initializing remove list

remove_list = [3, 6]

# Printing original list

print("The original list is : " + str(test_list))

# Printing remove list

print("The original list is : " + str(remove_list))

# Removing elements present in other list

# using list comprehension

res = [i for i in test_list if i not in remove_list]

# Printing the result

print("The list after performing remove operation is : " + str(res))

# removes item with given name in list

list = [15, 79, 709, "Back to your IDE"]

list.remove("Back to your IDE")

​

# removes last item in list

list.pop()

​

# pop() also works with an index...

list.pop(0)

​

# ...and returns also the "popped" item

item = list.pop()

l = list[1, 2, 3, 4]

l.pop(0) #remove item by index

l.remove(3)#remove item by value

#also buth of the methods returns the item

list.remove(item)

# delete by index

a = ['a', 'b', 'c', 'd']

a.pop(0)

print(a)

['b', 'c', 'd']

# Basic syntax:

my_list.remove(element) # or:

my_list.pop(index)

# Note, .remove(element) removes the first matching element it finds in

#   the list.

​

# Example usage:

animals = ['cat', 'dog', 'rabbit', 'guinea pig', 'rabbit']

animals.remove('rabbit')

print(animals)

--> ['cat', 'dog', 'guinea pig', 'rabbit']

# Note only the first instance of rabbit was removed from the list. 

​

# Note, if you want to remove all instances of an element (and it's the only

#   duplicated element), you could convert the list to a set then back to a

#   list, and then run .remove(element) E.g.:

animals = list(set['cat', 'dog', 'rabbit', 'guinea pig', 'rabbit'])

animals.remove('rabbit')

print(animals)

--> ['cat', 'dog', 'guinea pig']

# removes item with given name in list

list = [15, 79, 709, "Back to your IDE"]

list.remove("Back to your IDE")

​

# removes last item in list

list.pop()

​

# pop() also works with an index..

list.pop(0)

​

# ...and returns also the "popped" item

item = list.pop()

myList = ['Item', 'Item', 'Delete Me!', 'Item']

​

del myList[2] # myList now equals ['Item', 'Item', 'Item']

names = ['Boris', 'Steve', 'Phil', 'Archie']

names.pop(0) #removes Boris

names.remove('Steve') #removes Steve

l = ["a", "b", "c", "d", "e", "f", "g", "h", "i"]

del l[0]

print(l)

# deletes whole list

thislist = ["apple", "banana", "cherry"]

del thislist