c# cut n elements from start of array

Plat00n answered on December 14, 2023 Popularity 2/10 Helpfulness 1/10

answer c# cut n elements from start of array

c# cut n elements from start of array

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// There are multiple ways to do so.
// 1: Array.Skip
var cutArraySkip = arr.Skip(n).ToArray; 
// This returns the array with the first n elements cut off

// 2: Convert to List
// For small values of n, array.Skip is possible.
// When n becomes large, the Skip function is slow.
// An alternate, faster way to so this is by using lists:
List<T> list = new List<T>(arr);
list.RemoveRange(0, n);
var cutArrayList = list.ToArray();

// If every millisecond is important, one even faster way is to use a Span:
var cutArraySpan = arr.AsSpan().Slice(n).ToArray();

// Surprisingly, this is the fastest solution I found:

T[] buffer = new T[arr.Length - n];
int batchSize = 64;

Parallel.For(0, buffer.Length / batchSize, batchIndex =>
{
  for (int i = batchIndex * batchSize; i < (batchIndex + 1) * batchSize && i < buffer.Length; i++)
  {
    buffer[i + 2] = arr[i + n];
  }
});

Popularity 2/10 Helpfulness 1/10 Language typescript

Source: Grepper

Tags: c# cut elements n typescript

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Contributed on Dec 14 2023

Plat00n

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