python tic tac to game

Ahmed Abdellahi abdat answered on November 23, 2023 Popularity 4/10 Helpfulness 1/10

answer python tic tac to game

python tic tac to game

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import random

def print_board(board):
    for row in board:
        print(" | ".join(row))
        print("-" * 9)

def check_winner(board, player):
    # Check rows, columns, and diagonals
    for i in range(3):
        if all(board[i][j] == player for j in range(3)) or all(board[j][i] == player for j in range(3)):
            return True
    if all(board[i][i] == player for i in range(3)) or all(board[i][2 - i] == player for i in range(3)):
        return True
    return False

def is_board_full(board):
    return all(cell != ' ' for row in board for cell in row)

def get_user_move():
    while True:
        try:
            position = int(input("Enter a number between 1 and 9: "))
            if 1 <= position <= 9:
                return position - 1
            print("Invalid input. Please enter a number between 1 and 9.")
        except ValueError:
            print("Invalid input. Please enter a number between 1 and 9.")

def get_user_symbol():
    while True:
        user_choice = input("Choose 'X' or 'O': ").upper()
        if user_choice in ['X', 'O']:
            return user_choice
        print("Invalid choice. Please choose 'X' or 'O.")

def play_game():
    user_symbol = get_user_symbol()
    computer_symbol = 'X' if user_symbol == 'O' else 'O'
    board = [[' ' for _ in range(3)] for _ in range(3)]
    players = [user_symbol, computer_symbol]
    random.shuffle(players)  # Randomize the starting player
    current_player = players[0]

    while True:
        print_board(board)
        position = get_user_move() if current_player == user_symbol else random.choice([(i, j) for i in range(3) for j in range(3) if board[i][j] == ' '])
        row, col = divmod(position, 3)

        if board[row][col] == ' ':
            board[row][col] = current_player
            if check_winner(board, current_player):
                print_board(board)
                print(f"Congratulations! {current_player} wins!")
                break
            if is_board_full(board):
                print_board(board)
                print("It's a tie!")
                break
            current_player = players[1] if current_player == players[0] else players[0]
        else:
            print("The cell is already taken. Choose another one.")

if __name__ == "__main__":
    play_game()

Popularity 4/10 Helpfulness 1/10 Language python

Source: chat.openai.com

Tags: python tac

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Contributed on Nov 23 2023

Ahmed Abdellahi abdat

0 Answers Avg Quality 2/10

python tic tac to game

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