PalindromeChecker

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Precious Pollan answered on February 27, 2021 Popularity 3/10 Helpfulness 1/10

answer PalindromeChecker

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PalindromeChecker

Comment

public class PalindromeChecker {
    public static void main(String[] args) {
        String word = "racecar";
        if (isPalindrome(word)) {
            System.out.println(word + " is a palindrome.");
        } else {
            System.out.println(word + " is not a palindrome.");
        }
    }

    public static boolean isPalindrome(String word) {
        word = word.toLowerCase(); // Convert to lowercase for case-insensitive comparison
        int left = 0;
        int right = word.length() - 1;

        while (left < right) {
            if (word.charAt(left) != word.charAt(right)) {
                return false;
            }
            left++;
            right--;
        }

        return true;
    }
}

Popularity 3/10 Helpfulness 1/10 Language java

Source: chat.openai.com

Tags: java

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Contributed on Oct 22 2023

Precious Pollan

0 Answers Avg Quality 2/10

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Palindrome Checker

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/*
	C++ Palindrome Checker program by lolman_ks.
    Checks palindromic string WITHOUT reversing it.
    Same logic can be used to build this program in other languages.
*/
  
 /*
	 Logic: In a palindromic string, the 1st and last, 2nd and 2nd last, and so
     on characters are equal.
     Return false from the function if any of these matches, i.e (1st and last),
     (2nd and 2nd last) are not equal.
 */

#include <iostream>
using namespace std;

bool checkPalindromicString(string text){
  int counter_1 = 0; //Place one counter at the start.
  int counter_2 = text.length() - 1; //And the other at the end.

  //Run a loop till counter_2 is not less that counter_1.
  
  while(counter_2 >= counter_1){
    if(text[counter_1] != text[counter_2]) return false; //Check for match.
    //Note: Execution of a function is halted as soon as a value is returned.
    
    else{
      ++counter_1; //Move the first counter one place ahead.
      --counter_2; //Move the second character one place back.
    }
  }
  return true; 
  /*
  	Return true if the loop is not broken because of unequal characters and it
    runs till the end.
    If the loop runs till the condition specified in it, i.e 
    (counter_2 >= counter1), that means all matches are equal and the string is 
    palindromic.
  */
}

//Implementation of the function.

int main(){
  cout << checkPalindromicString("racecar") << endl; //Outputs 1 (true).
  cout << checkPalindromicString("text") << endl; //Outputs 0 (False).
  
  if(checkPalindromicString("lol")){
  	cout << "#lolman_ks";
  }
  //Outputs #lolman_ks.
  
  return 0;
}

//I hope this would be useful to you all, please promote this answer if it is.
//#lolman_ks

Popularity 10/10 Helpfulness 3/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Mar 04 2022

LOLMAN_KS

0 Answers Avg Quality 2/10

check for palindromes

Comment

function palindrome(str) {
  var re = /[\W_]/g;// representing Non-alphanumetic characters
  var lowRegStr = str.toLowerCase().replace(re, '');
  var reverseStr = lowRegStr.split('').reverse().join(''); 
  return reverseStr === lowRegStr;
}
palindrome("A man, a plan, a canal. Panama");

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: www.freecodecamp.org

Tags: javascript j

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Contributed on Mar 25 2022

Ernest Adonu

0 Answers Avg Quality 2/10

Palindrome check

Comment

bool isPalindrom(string str){
    for (int i = 0; i < str.length(); i++)
       if(str[i]!=str[str.length()-i]) return false;
    return true;
}

Popularity 10/10 Helpfulness 2/10 Language cpp

Source: Grepper

Tags: c++

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Contributed on Sep 26 2023

Shishir Bhuiyan

0 Answers Avg Quality 2/10

Palindrome Checker

Comment

// The Setup
function palindrome(str) {

  // Using Regex to remove all the special character, converted all the string to lowercase to ease working with and assign it to a new variable 
  let newStr = str.replace(/[^a-zA-Z0-9]/g, '').toLowerCase();

  // Split the string, reverse, join then assign it to a new variable
  let revStr = newStr.split('').reverse().join('');

  // return their value
  return newStr === revStr;

}

palindrome("A man, a plan, a canal. Panama");

Popularity 7/10 Helpfulness 2/10 Language javascript

Source: Grepper

Tags: javascript palindrome p

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Contributed on Jul 23 2022

Taiwo Jazz

0 Answers Avg Quality 2/10

Palindrome Checker

Comment

const palindrome = str = {
  str = str.replace(/[\W+|_]/g, '').toLowerCase()
  
  const str1 = str.split('').reverse().join('')

  return str1 === str
}

palindrome("My age is 0, 0 si ega ym.");

// With love @kouqhar

Popularity 10/10 Helpfulness 2/10 Language javascript

Source: www.linkedin.com

Tags: javascript j

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Contributed on Feb 27 2021

kouqhar

0 Answers Avg Quality 2/10

Valid Palindrome

Comment

class Solution :
   def isPalindrome(self, string: str ) :
       '''
       A function to check if a string is Palindrome or not!
       :param string: string to be checked
       :return: True if it is palindrome else False
       '''
       string = string.lower()
       s_stripped = ''.join(list( filter ( lambda x : x.isalnum () == True , string)))
       return s_stripped == s_stripped[::-1]


if __name__ == '__main__' :
   string = 'Was it a car or a cat I saw!!'
   print (f'Is "{string}" a palindrome? : {Solution ().isPalindrome (string)}')
   string2 = 'A man, a plan,'
   print (f'Is "{string2}" a palindrome? : {Solution ().isPalindrome (string2)}')

Popularity 10/10 Helpfulness 1/10 Language python

Source: favtutor.com

Tags: palindrome p

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Contributed on Jan 24 2022

Itchy Impala

0 Answers Avg Quality 2/10

can be palindrome

Comment

// can we generate palindrome string by suffling 
// the character of the string s 
public bool CanBePalindrome(string s)
{
    var dict = new Dictionary<char, int>();
    for (int j =0; j < s.Length; j++)
    {
        var item = s[j];
        if (dict.ContainsKey(item))
        {
            dict[item]++;
            if (dict[item] == 2)
            {
                dict.Remove(item);
            }
        }
        else
        {
            dict.Add(item, 1);
        }
    }
    return dict.Count <= 1;
}

Popularity 10/10 Helpfulness 1/10 Language csharp

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Tags: c# c

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Contributed on Jun 29 2022

PrashantUnity

0 Answers Avg Quality 2/10

valid palindrome

Comment

-1

anything

Popularity 9/10 Helpfulness 1/10 Language whatever

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Tags: palindrome p

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Contributed on Aug 23 2022

Rainer Rilke

0 Answers Avg Quality 2/10

PalindromeChecker

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