how api router from python

Hurt Hyena answered on June 16, 2023 Popularity 3/10 Helpfulness 1/10

answer how api router from python

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how api router from python

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import flask
from flask import request, jsonify

app = flask.Flask(__name__)
app.config["DEBUG"] = True

# Create some test data for our catalog in the form of a list of dictionaries.
books = [
    {'id': 0,
     'title': 'A Fire Upon the Deep',
     'author': 'Vernor Vinge',
     'first_sentence': 'The coldsleep itself was dreamless.',
     'year_published': '1992'},
    {'id': 1,
     'title': 'The Ones Who Walk Away From Omelas',
     'author': 'Ursula K. Le Guin',
     'first_sentence': 'With a clamor of bells that set the swallows soaring, the Festival of Summer came to the city Omelas, bright-towered by the sea.',
     'published': '1973'},
    {'id': 2,
     'title': 'Dhalgren',
     'author': 'Samuel R. Delany',
     'first_sentence': 'to wound the autumnal city.',
     'published': '1975'}
]


@app.route('/', methods=['GET'])
def home():
    return '''<h1>Distant Reading Archive</h1>
<p>A prototype API for distant reading of science fiction novels.</p>'''


# A route to return all of the available entries in our catalog.
@app.route('/api/v1/resources/books/all', methods=['GET'])
def api_all():
    return jsonify(books)

app.run()

Popularity 3/10 Helpfulness 1/10 Language python

Source: programminghistorian.org

Tags: api python router

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Contributed on Jun 16 2023

Hurt Hyena

0 Answers Avg Quality 2/10

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how api router from python

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import flask
from flask import request, jsonify
import sqlite3

app = flask.Flask(__name__)
app.config["DEBUG"] = True

def dict_factory(cursor, row):
    d = {}
    for idx, col in enumerate(cursor.description):
        d[col[0]] = row[idx]
    return d


@app.route('/', methods=['GET'])
def home():
    return '''<h1>Distant Reading Archive</h1>
<p>A prototype API for distant reading of science fiction novels.</p>'''


@app.route('/api/v1/resources/books/all', methods=['GET'])
def api_all():
    conn = sqlite3.connect('books.db')
    conn.row_factory = dict_factory
    cur = conn.cursor()
    all_books = cur.execute('SELECT * FROM books;').fetchall()

    return jsonify(all_books)



@app.errorhandler(404)
def page_not_found(e):
    return "<h1>404</h1><p>The resource could not be found.</p>", 404


@app.route('/api/v1/resources/books', methods=['GET'])
def api_filter():
    query_parameters = request.args

    id = query_parameters.get('id')
    published = query_parameters.get('published')
    author = query_parameters.get('author')

    query = "SELECT * FROM books WHERE"
    to_filter = []

    if id:
        query += ' id=? AND'
        to_filter.append(id)
    if published:
        query += ' published=? AND'
        to_filter.append(published)
    if author:
        query += ' author=? AND'
        to_filter.append(author)
    if not (id or published or author):
        return page_not_found(404)

    query = query[:-4] + ';'

    conn = sqlite3.connect('books.db')
    conn.row_factory = dict_factory
    cur = conn.cursor()

    results = cur.execute(query, to_filter).fetchall()

    return jsonify(results)

app.run()

Popularity 3/10 Helpfulness 1/10 Language python

Source: programminghistorian.org

Tags: router api python

Link to this answer
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Contributed on Jun 16 2023

Hurt Hyena

0 Answers Avg Quality 2/10

how api router from python

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