networkx or pydot

Lazy Lion answered on April 3, 2023 Popularity 1/10 Helpfulness 1/10

answer networkx or pydot

networkx or pydot

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import math

import networkx as nx
from networkx.drawing.nx_pydot import to_pydot

g_list = [
    ("Alpha", "Alpha", 7.06),
    ("Alpha", "Bravo", 0.98),
    ("Alpha", "Charlie", 0.0),
    ("Alpha", "Delta", 0.0),
    ("Alpha", "Echo", 1.57),
    ("Alpha", "Foxtrot", 2.16),
    ("Alpha", "Golf", 1.57),
    ("Alpha", "Hotel", 0.39),
    ("Alpha", "India", 0.0),
    ("Alpha", "Juliet", 0.2),
    ("Alpha", "Kilo", 0.59),
    ("Bravo", "Alpha", 1.66),
    ("Bravo", "Bravo", 8.54),
    ("Bravo", "Charlie", 1.21),
    ("Bravo", "Delta", 1.78),
    ("Bravo", "Echo", 0.25),
    ("Bravo", "Foxtrot", 0.76),
    ("Bravo", "Golf", 1.66),
    ("Bravo", "Hotel", 1.59),
    ("Bravo", "India", 2.87),
    ("Bravo", "Juliet", 1.72),
    ("Bravo", "Kilo", 1.27),
    ("Charlie", "Alpha", 1.0),
    ("Charlie", "Bravo", 2.5),
    ("Charlie", "Charlie", 7.0),
    ("Charlie", "Delta", 5.0),
    ("Charlie", "Echo", 0.0),
    ("Charlie", "Foxtrot", 0.5),
    ("Charlie", "Golf", 3.0),
    ("Charlie", "Hotel", 0.0),
    ("Charlie", "India", 0.5),
    ("Charlie", "Juliet", 2.5),
    ("Charlie", "Kilo", 1.5),
]

graph = nx.DiGraph()
# Add edges, but reverse direction, remove self-loops, and remove zero-weight edges
graph.add_weighted_edges_from([(b, a, w) for (a, b, w) in g_list if w > 0 and a != b])

for edge in graph.edges().values():
    edge["penwidth"] = round(1 + math.sqrt(edge["weight"]), 2)

p = to_pydot(graph)
p.write_png("graph.png")

Popularity 1/10 Helpfulness 1/10 Language whatever

Source: stackoverflow.com

Tags: networkx pydot whatever

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Contributed on Apr 03 2023

Lazy Lion

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networkx or pydot

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