Group by array of objects javascript

Samiksha Singla answered on August 5, 2019 Popularity 9/10 Helpfulness 3/10

answer Group by array of objects javascript

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Group by array of objects javascript

Comment

var groupBy = function(xs, key) {
  return xs.reduce(function(rv, x) {
    (rv[x[key]] = rv[x[key]] || []).push(x);
    return rv;
  }, {});
};

console.log(groupBy(['one', 'two', 'three'], 'length'));

// => {"3": ["one", "two"], "5": ["three"]}
 Run code snippet

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Source: stackoverflow.com

Tags: group-by javascript

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Contributed on Mar 22 2023

Samiksha Singla

0 Answers Avg Quality 2/10

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javascript group by property array of objects

Comment

function groupArrayOfObjects(list, key) {
  return list.reduce(function(rv, x) {
    (rv[x[key]] = rv[x[key]] || []).push(x);
    return rv;
  }, {});
};

var people = [
    {sex:"Male", name:"Jeff"},
    {sex:"Female", name:"Megan"},
    {sex:"Male", name:"Taylor"},
    {sex:"Female", name:"Madison"}
];
var groupedPeople=groupArrayOfObjects(people,"sex");
console.log(groupedPeople.Male);//will be the Males 
console.log(groupedPeople.Female);//will be the Females

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Contributed on Aug 05 2019

Grepper

0 Answers Avg Quality 2/10

Group an Array By an Object Property, array, object

Comment

const groupBy = (arr, groupFn) =>
  arr.reduce(
    (grouped, obj) => ({
      ...grouped,
      [groupFn(obj)]: [...(grouped[groupFn(obj)] || []), obj],
    }),
    {}
  );
const people = [
  { name: 'Matt' },
  { name: 'Sam' },
  { name: 'John' },
  { name: 'Mac' },
];
const groupedByNameLength = groupBy(people, (person) => person.name.length);
/**
{
  '3': [ { name: 'Sam' }, { name: 'Mac' } ],
  '4': [ { name: 'Matt' }, { name: 'John' } ]
}
 */
console.log(groupedByNameLength);

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Contributed on Aug 12 2022

sanjai

0 Answers Avg Quality 2/10

how to group an array of objects

Comment

const groupBy = (array, key) => {
  // Return the end result
  return array.reduce((result, currentValue) => {
    // If an array already present for key, push it to the array. Else create an array and push the object
    (result[currentValue[key]] = result[currentValue[key]] || []).push(
      currentValue
    );
    // Return the current iteration `result` value, this will be taken as next iteration `result` value and accumulate
    return result;
  }, {}); // empty object is the initial value for result object
};

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Source: Grepper

Tags: group grou

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Contributed on Apr 29 2022

Better Butterfly

0 Answers Avg Quality 2/10

Group by array of objects javascript

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