c# generate random string of length
c# generate random string of length
xxxxxxxxxxstatic string GenerateRandomString(int length){ const string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789"; var random = new Random(); return new string(Enumerable.Repeat(chars, length) .Select(s => s[random.Next(s.Length)]).ToArray());}string randomStr = GenerateRandomString(10);Console.WriteLine(randomStr); // Output: a random string of 10 charactersthe GenerateRandomString() method takes an integer argument length that specifies the length of the random string to generate. The chars variable defines a character set that includes upper and lowercase letters and digits. The Random class is used to generate a random index into the character set for each character in the random string, and the resulting characters are concatenated into a new string.
The Enumerable.Repeat() method is used to repeat the character set length times, and the Select() method is used to randomly select a character from each repeated character set. The resulting characters are combined into an array using the ToArray() method, and then passed to the string constructor to create the final random string.
Note that you need to include the System.Linq namespace to use the Enumerable class.
Closely Related Answers
xxxxxxxxxxprivate static Random random = new Random();public static string RandomString(int length){ const string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"; return new string(Enumerable.Repeat(chars, length) .Select(s => s[random.Next(s.Length)]).ToArray());}
xxxxxxxxxxprivate static Random random = new Random();public static string RandomString(int length){ const string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"; return new string(Enumerable.Repeat(chars, length) .Select(s => s[random.Next(s.Length)]).ToArray());}
xxxxxxxxxxprivate static Random random = new Random();public static string RandomString(int length){ const string chars = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"; return new string(Enumerable.Repeat(chars, length) .Select(s => s[random.Next(s.Length)]).ToArray());}
xxxxxxxxxxpublic static string CreateRandomString(int size){ StringBuilder builder = new StringBuilder(); Random random = new Random(); char c; for(int i=0; i < size; i++) { c = Convert.ToChar(Convert.ToInt32(Math.Floor(26 * random.NextDouble() + 65))); builder.Append(c); } return builder.ToString();}
Twitter 
LinkedIn