# If iterable/container is indexed => slicing is possible, then we can use

# for loop in 2 more ways to iterate over it [apart from usual for x in a: ]

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# 1-> using range function to create an iterable object 

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a=[1,2,4,4,5,7,8]

b=a[:] # or b=list(a), basically creating copy of a in b

for i in range(len(a)):

    a.pop()

    print(i,b[i],a)

    # note that a decreases with each pop so we used b in print to access 

    # original elements using b[i] not a[i]

# NOTE: range(len(a)) will create a iterable object(which isn't object of a)

# which will remain unnafected by a.pop() which acts on object of a

# ALSO NOTE that range() functions just like slicing. 

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# 2-> using list(enumerate()) to create an iterable object 

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a=[1,2,4,4,5,7,8]

for x,y in list(enumerate(a)):

    a.pop()

    print(x,y,a)

# NOTE: list(enumerate(a)) will create a iterable object(which isn't

# object that a points to) which will remain unnafected by a.pop() 

# which acts on object of a.

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## ALSO NOTE BOTH PYTHON CODES ABOVE HAVE SAME OUTPUT.

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for index, value in enumerate(iterator):

    print(index, value)

colors = ["red", "green", "blue", "purple"]

ratios = [0.2, 0.3, 0.1, 0.4]

for color, ratio in zip(colors, ratios):

    print("{}% {}".format(ratio * 100, color))

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