Tree traversal in C++

Hilarious Heron answered on March 24, 2021 Popularity 9/10 Helpfulness 1/10

answer Tree traversal in C++

related preorder traversal of binary tree c++

related preorder traversal c++

Tree traversal in C++

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// Tree traversal in C++

#include <iostream>
using namespace std;

struct Node {
  int data;
  struct Node *left, *right;
  Node(int data) {
    this->data = data;
    left = right = NULL;
  }
};

// Preorder traversal
void preorderTraversal(struct Node* node) {
  if (node == NULL)
    return;

  cout << node->data << "->";
  preorderTraversal(node->left);
  preorderTraversal(node->right);
}

// Postorder traversal
void postorderTraversal(struct Node* node) {
  if (node == NULL)
    return;

  postorderTraversal(node->left);
  postorderTraversal(node->right);
  cout << node->data << "->";
}

// Inorder traversal
void inorderTraversal(struct Node* node) {
  if (node == NULL)
    return;

  inorderTraversal(node->left);
  cout << node->data << "->";
  inorderTraversal(node->right);
}

int main() {
  struct Node* root = new Node(1);
  root->left = new Node(12);
  root->right = new Node(9);
  root->left->left = new Node(5);
  root->left->right = new Node(6);

  cout << "Inorder traversal ";
  inorderTraversal(root);

  cout << "\nPreorder traversal ";
  preorderTraversal(root);

  cout << "\nPostorder traversal ";
  postorderTraversal(root);

Popularity 9/10 Helpfulness 1/10 Language cpp

Source: www.programiz.com

Tags: c++ tree-traversal

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Contributed on Dec 26 2022

Hilarious Heron

0 Answers Avg Quality 2/10

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preorder traversal of binary tree c++

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#include <bits/stdc++.h>

using namespace std;

struct node {
  int data;
  struct node * left, * right;
};

vector < int > preOrderTrav(node * curr) {
  vector < int > preOrder;
  if (curr == NULL)
    return preOrder;

  stack < node * > s;
  s.push(curr);

  while (!s.empty()) {
    node * topNode = s.top();
    preOrder.push_back(topNode -> data);
    s.pop();
    if (topNode -> right != NULL)
      s.push(topNode -> right);
    if (topNode -> left != NULL)
      s.push(topNode -> left);
  }
  return preOrder;

}

struct node * newNode(int data) {
  struct node * node = (struct node * ) malloc(sizeof(struct node));
  node -> data = data;
  node -> left = NULL;
  node -> right = NULL;

  return (node);
}

int main() {

  struct node * root = newNode(1);
  root -> left = newNode(2);
  root -> right = newNode(3);
  root -> left -> left = newNode(4);
  root -> left -> right = newNode(5);
  root -> left -> right -> left = newNode(8);
  root -> right -> left = newNode(6);
  root -> right -> right = newNode(7);
  root -> right -> right -> left = newNode(9);
  root -> right -> right -> right = newNode(10);

  vector < int > preOrder;
  preOrder = preOrderTrav(root);

  cout << "The preOrder Traversal is : ";
  for (int i = 0; i < preOrder.size(); i++) {
    cout << preOrder[i] << " ";
  }
  return 0;
}

Popularity 9/10 Helpfulness 1/10 Language cpp

Source: takeuforward.org

Tags: binary-tree bina

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Contributed on Dec 10 2023

Hitesh Prajapati

0 Answers Avg Quality 2/10

preorder traversal c++

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a
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Popularity 1/10 Helpfulness 1/10 Language cpp

Source: Grepper

Tags: c++ preorder traversal

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Contributed on Mar 24 2021

Jolly Jackal

0 Answers Avg Quality 2/10

Tree traversal in C++

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