#Whether a number is perfect square or not?

#article: https://www.cuemath.com/algebra/perfect-squares/

import math

​

def is_square(n):

    return n > -1 and math.sqrt(n) %1 == 0

​

n = int(input())

res = is_square(n)

if res:

    print(f"Your {n} is perfect number.")

else:

    print(f"Your {n} isn't perfect number.")

import math

​

def is_square(n):

    return n > -1 and math.sqrt(n) % 1 == 0

​

​

# Taking the input from user

number = int(input("Enter the Number: "))

if is_square(number):

    print(f'Your number: {number} is perfect square.')

else:

    print(f'Your number: {number} is not perfect square.')

import math

​

def is_perfect_square(number: int) -> bool:

    """

    Returns True if the provided number is a

    perfect square (and False otherwise).

    """

    return math.isqrt(number) ** 2 == number