# list.sort sorts the list in place, i.e. it doesn't return a new list. Just write

newList.sort()

return newList

# The problem is here:

answer = newList.sort()

# sort does not return the sorted list; rather, it sorts the list in place.

​

#Use:

answer = sorted(newList)

because .sort() modifies the original list, so you can just do:

my_list = [6, 5, 4]

my_list.sort()

print(my_list)

>>> xs = [None, 1, 3, None, 2]

​

>>> sorted(xs, key=lambda x: (x is None, x))

[1, 2, 3, None, None]

​

>>> sorted(xs, key=lambda x: (x is not None, x))

[None, None, 1, 2, 3]

​

>>> sorted(xs, key=lambda x: (x is None, x), reverse=True)

[None, None, 3, 2, 1]

​

>>> sorted(xs, key=lambda x: (x is not None, x), reverse=True)

[3, 2, 1, None, None]