python counter

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Jerome Scott answered on March 11, 2020 Popularity 10/10 Helpfulness 4/10

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import collections

arr = ['a', 'a', 'b', 'b', 'b', 'c']

# set the elements frequencies using Counter class
elements_count = collections.Counter(arr)

# printing the element and the frequency
for key, value in elements_count.items():
    print(f"{key}: {value}")

# output
# a: 2
# b: 3
# c: 1


data = 'hello world'

# set the elements frequencies using Counter class
elements_count = collections.Counter(data)

# printing the element and the frequency
print(elements_count)

Popularity 10/10 Helpfulness 4/10 Language python

Source: codefreelance.net

Tags: counter python

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Contributed on Sep 01 2022

Jerome Scott

0 Answers Avg Quality 2/10

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Counter in python

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from collections import Counter
strl = "aabbaba"
print(Counter(str1))

Counter({'a': 4, 'b': 3})

Popularity 10/10 Helpfulness 7/10 Language python

Source: stackoverflow.com

Tags: counter

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Contributed on Aug 16 2021

Tender Tuatara

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python Counter()

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# PYTHON 3
from collections import Counter
def example(data: str) -> Counter:
	counted_letters = Counter(data) # Counts every character in the string
    return counted_letters # {character: amount}
    
example('Data1233') # Counter({'D': 1, 'a': 2, 't': 1, '1': 1, '2': 1, '3': 2})
example('hello world') # Counter({'h': 1, 'e': 1, 'l': 3, 'o': 2, ' ': 1, 'w': 1, 'r': 1, 'd': 1})

Popularity 9/10 Helpfulness 5/10 Language python

Source: docs.python.org

Tags: character char

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Contributed on Jun 10 2024

Programmer

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counter library python

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import collections

c = collections.Counter()
print 'Initial :', c

c.update('abcdaab')
print 'Sequence:', c

c.update({'a':1, 'd':5})
print 'Dict    :', c

Popularity 10/10 Helpfulness 5/10 Language python

Source: pymotw.com

Tags: python py

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Contributed on Sep 05 2022

Jealous Jaguar

0 Answers Avg Quality 2/10

counter in python

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import collections

print collections.Counter(['a', 'b', 'c', 'a', 'b', 'b'])
print collections.Counter({'a':2, 'b':3, 'c':1})
print collections.Counter(a=2, b=3, c=1)

Popularity 10/10 Helpfulness 4/10 Language python

Source: pymotw.com

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Contributed on Mar 05 2021

Relieved Reindeer

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python counter

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>>> from collections import Counter
>>> colors = ['blue', 'blue', 'blue', 'red', 'red']
>>> counter = Counter(colors)
>>> counter['yellow'] += 1
Counter({'blue': 3, 'red': 2, 'yellow': 1})
>>> counter.most_common()[0]
('blue', 3)

Popularity 10/10 Helpfulness 4/10 Language python

Source: gto76.github.io

Tags: counter

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Contributed on Mar 10 2022

Michael

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.counter python

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import collections

number = [0, 0, 0, 1, 1, 0, 0, 0, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0, 0, 1, 1]
collections.Counter(number)

#output
#Counter({0: 12, 1: 9})

Popularity 9/10 Helpfulness 3/10 Language python

Source: Grepper

Tags: python py

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Contributed on Sep 02 2022

Pleasant Peccary

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counter python

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>>> # Tally occurrences of words in a list
>>> cnt = Counter()
>>> for word in ['red', 'blue', 'red', 'green', 'blue', 'blue']:
...     cnt[word] += 1
>>> cnt
Counter({'blue': 3, 'red': 2, 'green': 1})

>>> # Find the ten most common words in Hamlet
>>> import re
>>> words = re.findall(r'\w+', open('hamlet.txt').read().lower())
>>> Counter(words).most_common(10)
[('the', 1143), ('and', 966), ('to', 762), ('of', 669), ('i', 631),
 ('you', 554),  ('a', 546), ('my', 514), ('hamlet', 471), ('in', 451)]

Popularity 9/10 Helpfulness 3/10 Language python

Source: docs.python.org

Tags: counter

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Contributed on Sep 03 2022

Vickyrules

0 Answers Avg Quality 2/10

python counter

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>>> Counter('abracadabra').most_common(3)
[('a', 5), ('r', 2), ('b', 2)]

Popularity 10/10 Helpfulness 3/10 Language python

Source: docs.python.org

Tags: counter

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Contributed on Mar 11 2020

Foolish Flamingo

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python counter

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sum(c.values())                 # total of all counts
c.clear()                       # reset all counts
list(c)                         # list unique elements
set(c)                          # convert to a set
dict(c)                         # convert to a regular dictionary
c.items()                       # convert to a list of (elem, cnt) pairs
Counter(dict(list_of_pairs))    # convert from a list of (elem, cnt) pairs
c.most_common()[:-n-1:-1]       # n least common elements
c += Counter()                  # remove zero and negative counts

Popularity 10/10 Helpfulness 2/10 Language python

Source: docs.python.org

Tags: counter

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Contributed on Mar 11 2020

Foolish Flamingo

0 Answers Avg Quality 2/10

python counter

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