assembly sqrt 8086

DarkMode answered on August 20, 2022 Popularity 6/10 Helpfulness 3/10

answer assembly sqrt 8086

assembly sqrt 8086

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; 8086
; SQRT(BX:x)
; x: Input number to calculate square root
;    supported range for x is [0, 256]
; Output(g)
; Requirement: IsOdd
; Uses: AX, DX (Preserved)
.data
    g     dd 0x00FF
    c     dd 0x00FF
SQRT:
    push ax
    push dx
    cmp bx, 0
    jg SQRT_Input_Greater_Than_Zero
        mov g, 0
        pop dx
        pop ax
        ret
    SQRT_Input_Greater_Than_Zero:
    push ax
    push dx
    mov dx, 0x00FF
    mov g, dx
    mov c, dx 
    SQRT_While_True_Processing_Loop:
        mov ax, g
        mul g
        cmp ax, bx
        jna EndOfG_Squared_Greater_Than_X
            mov dx, c
            xor g, dx
        EndOfG_Squared_Greater_Than_X:
        shr c, 1
        cmp c, 0
        jne EndOfC_Is_Zero
            mov ax, bx
            call IsOdd
            cmp dx, 1
            je SQRT_Input_Not_Even
                inc g
            SQRT_Input_Not_Even:
            pop dx
            pop ax
            ret
        EndOfC_Is_Zero:
        mov dx, c
        or g, dx
    jmp SQRT_While_True_Processing_Loop
; IsOdd(AX:x)
; x: Input number to check if it is odd
; Output(DX):
;   1: Is odd
;   0: Is even
IsOdd:
    mov dx, 1
    and dx, ax
    ret

Popularity 6/10 Helpfulness 3/10 Language assembly

Source: Grepper

Tags: assembly sqrt square-root

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Contributed on Aug 20 2022

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