split xml file into multiple files in java

avinash jadav answered on July 20, 2022 Popularity 5/10 Helpfulness 1/10

answer split xml file into multiple files in java

split xml file into multiple files in java

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import java.io.File;
import java.util.ArrayList;
import java.util.List;

import javax.xml.parsers.DocumentBuilder;
import javax.xml.parsers.DocumentBuilderFactory;
import javax.xml.transform.OutputKeys;
import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.dom.DOMSource;
import javax.xml.transform.stream.StreamResult;
import javax.xml.xpath.XPath;
import javax.xml.xpath.XPathConstants;
import javax.xml.xpath.XPathExpression;
import javax.xml.xpath.XPathFactory;

import org.w3c.dom.Document;
import org.w3c.dom.Element;
import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

public class ExtractXml
{
    /**
     * @param args
     */
    public static void main(String[] args) throws Exception
    {
        String inputFile = "resources/products.xml";

        File xmlFile = new File(inputFile);
        DocumentBuilderFactory dbFactory = DocumentBuilderFactory.newInstance();
        DocumentBuilder dBuilder = dbFactory.newDocumentBuilder();
        Document doc = dBuilder.parse(xmlFile);

        DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
        factory.setNamespaceAware(true); // never forget this!

        XPathFactory xfactory = XPathFactory.newInstance();
        XPath xpath = xfactory.newXPath();
        XPathExpression allProductsExpression = xpath.compile("//product/supplier/text()");
        NodeList productNodes = (NodeList) allProductsExpression.evaluate(doc, XPathConstants.NODESET);

        //Save all the products
        List<String> suppliers = new ArrayList<String>();
        for (int i=0; i<productNodes.getLength(); ++i)
        {
            Node productName = productNodes.item(i);

            System.out.println(productName.getTextContent());
            suppliers.add(productName.getTextContent());
        }

        //Now we create the split XMLs

        for (String supplier : suppliers)
        {
            String xpathQuery = "/products/product[supplier='" + supplier + "']";

            xpath = xfactory.newXPath();
            XPathExpression query = xpath.compile(xpathQuery);
            NodeList productNodesFiltered = (NodeList) query.evaluate(doc, XPathConstants.NODESET);

            System.out.println("Found " + productNodesFiltered.getLength() + 
                               " product(s) for supplier " + supplier);

            //We store the new XML file in supplierName.xml e.g. Sony.xml
            Document suppXml = dBuilder.newDocument();

            //we have to recreate the root node <products>
            Element root = suppXml.createElement("products"); 
            suppXml.appendChild(root);
            for (int i=0; i<productNodesFiltered.getLength(); ++i)
            {
                Node productNode = productNodesFiltered.item(i);

                //we append a product (cloned) to the new file
                Node clonedNode = productNode.cloneNode(true);
                suppXml.adoptNode(clonedNode); //We adopt the orphan :)
                root.appendChild(clonedNode);
            }

            //At the end, we save the file XML on disk
            TransformerFactory transformerFactory = TransformerFactory.newInstance();
            Transformer transformer = transformerFactory.newTransformer();
            transformer.setOutputProperty(OutputKeys.INDENT, "yes");
            DOMSource source = new DOMSource(suppXml);

            StreamResult result =  new StreamResult(new File("resources/" + supplier.trim() + ".xml"));
            transformer.transform(source, result);

            System.out.println("Done for " + supplier);
        }
    }

}

Popularity 5/10 Helpfulness 1/10 Language java

Source: stackoverflow.com

Tags: file java xml

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Contributed on Jul 20 2022

avinash jadav

0 Answers Avg Quality 2/10

split xml file into multiple files in java

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