student_grades = [9.1, 8.8, 10.0, 7.7, 6.8, 8.0, 10.0, 8.1, 10.0, 9.9]

​

samebnumber = student_grades.count(10.0)

​

print(samebnumber)

from collections import Counter

​

1ist1 = ['Peter', 'Rose', 'Donald', 'Peter']

a = Counter(listl).get('Peter')

​

print(f'Peter appears in the list {a} times')

​

# Output:

# Peter appears in the list 2 times

indices = [index for index, element in enumerate(a_list) if element == 1]

#import the Counter class from collections module

from collections import Counter

​

#An iterable with elements to count

data = 'aabbbccccdeefff'

​

#create the Counter object

c = Counter(data)

​

print(c)

​

#get the count of a specific element

print(c['f'])

# Basic syntax:

your_list.count("element")

​

# Example usage:

your_list = [12, 54, 67, 86, 89, 12, 54, 67, 67, 66]

your_list.count(67)

--> 3

#Count the frequency of elements in a list using dictionary

l=eva1.l(input("Enter the list"))

d={}

print(l)

for i in l:

if i not in d:

d[i]=l.count(i)

else:

pass

print("Frequency of element:")

​

for i in d:

print(i,"-",d[i])

output:

Enter the list[1,5,8,7,5,6,3,2,4,7,5,1,]

[1, 5, 8, 7, 5, 6, 3, 2, 4, 7, 5, 1]

Frequency of element:

1 - 2

5 - 3

8 - 1

7 - 2

6 - 1

3 - 1

2 - 1

4 - 1

Map<String, Long> counts =

    list.stream().collect(Collectors.groupingBy(e -> e, Collectors.counting()));