// program to print the value of i

​

#include <iostream>

using namespace std;

​

int main() {

    for (int i = 1; i <= 5; i++) {

        // break condition     

        if (i == 3) {

            break;

        }

        cout << i << endl;

    }

​

return 0;

}

break; statement helps in coming out of the current loop

Further in case of nested loop it gets you out of the innermost loop.

/*Q;Design a program to print the employee IDs starting

from 1 until an Id occur who have resigned. IDs of

resigned persons are 7 and 10 .*/

​

#include<iostream>

using namespace std;

int main()

{

    int meet=0;

    for(int i=1;i<30;i++) 

        {

            if(i==7||i==10)

            break;

            else

                meet=1;

        cout<<"Employee ID:"<<i<<endl;

        }

    return 0;

}

#include <iostream>

​

int main()

{

 while(1)

 {

   while(1)

   {

     // break; 

     //break only breaks the inner loop, so this will not work

     // to exit the outer loop, you'll have to use 'goto':

     goto breakOuter;

   }

   // IMPORTANT: Any code that happens after the inner loop will NOT be run

   // when using the goto!

   std::cout << "This won't be printed on the console" << std::endl;

 }

breakOuter: // This is the point where goto will jump to

  std::cout << "exited outer loop" << std::endl;

  return 0;

}

for (int i = 0; i < 10; i++) {

  if (i == 4) {

    continue;

  }

  cout << i << "\n";

}