sorting array based on other array

Ngoc Chau answered on April 8, 2022 Popularity 1/10 Helpfulness 1/10

answer sorting array based on other array

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sorting array based on other array

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function sort(initialArray, sortingArray){
  let newArr = [];
  for (let i = 0; i< initialArray.length; i++){
    newArr.push(initialArray[sortingArray.indexOf(i)])
  }
  return newArr
}

console.log(sort([1, 2, 3, 4, 5], [0, 2, 1, 4, 3]))

///////////////// OR ///////////////////////////////////
function sort(a, b) {
  return a.map((n,i)=>a[b.indexOf(i)])
}

///////////////// OR ///////////////////////////////////
function sort(initialArray, sortingArray) {
  const result = [];
  sortingArray.forEach((el, i) => result[el] = initialArray[i]);
  return result;
}

Popularity 1/10 Helpfulness 1/10 Language javascript

Source: Grepper

Tags: javascript sorting

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Contributed on Apr 08 2022

Ngoc Chau

0 Answers Avg Quality 2/10

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Popularity 3/10 Helpfulness 1/10 Language html

Source: space.barisx.com

Tags: html codepen highlight stylish

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Contributed on Nov 29 2024

barisx

0 Answers Avg Quality 2/10

sorting array based on other array

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