fibonacci using recursion

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Itchy Iguana answered on July 15, 2021 Popularity 10/10 Helpfulness 4/10

answer fibonacci using recursion

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fibonacci using recursion

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int fib (int n) {
        if (n < 2)
            return 1;
        return fib(n-1) + fib(n-2);
    }

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Source: www.hackerearth.com

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Contributed on Mar 25 2022

Itchy Iguana

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fibonacci series using recursion

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def fib (n):
  if n == 0 or n ==1:
      return n  
  else:
        return fib(n-2) + fib(n-1)
#n = int(input("please enter a number  "))

n=10
for index,num in enumerate(range(n+1)):
     print(f"F{index} :", fib(num))

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Source: onecompiler.com

Tags: fibonacci fibo

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Contributed on Dec 29 2021

Bloody Bat

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fibonacci series using recursion

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def fibonacci(n):
    if n <= 1:
          return n
    else:
        return fibonacci(n - 1) + fibonacci(n - 2)

n = int(input())
result = fibonacci(n)
print(result)

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Source: learning.ccbp.in

Tags: fibonacci fibo

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Contributed on Aug 26 2022

Vijay Potnuru

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fibonacci recursion

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function fib(n) {
    if (n === 1 || n === 0)
        return n

    return fib(n - 1) + fib(n - 2)
}
console.log('fib:', fib(9))		// [Log]: fib: 34

/*
    Time complexity O(2^n)
    Space complexity O(n)
    Since fib(n-1) gets evaluated completely before fib(n-2), 
    there will never be more than n levels of recursion.
*/

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Source: Grepper

Tags: fibonacci fibo

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Contributed on Jun 30 2022

Mysterious Macaque

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recursive fibonacci

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    def fibo2(n):
        if n ==1 or n==0:
            return 1
        else :
            n = n+fibo2(n-1) 
            return n 
    print(fibo2(n1))

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Contributed on Jul 15 2021

kirito.

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fibonacci series using recursion

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// Fibonacci serise using time complexity of O(n)=n or optimal time complexity
#include <iostream>
using namespace std;

int fArr[10];

int Fibo(int n){
    if(n <= 1){ //base class. Setting the first 2 index value to 0 &1
        fArr[n] = n;
        return n;
    }else{
        if(fArr[n-2] == -1){//if no values in the array then by default -1 will be there as default value
            fArr[n-2] = Fibo(n-2); // making a recursive call if the value doesn't present in the array
        }
        if(fArr[n-1] == -1){
            fArr[n-1] = Fibo(n-1);
        }
        return fArr[n-2] + fArr[n-1];
    }
}

int main() {
    int term;
    cout << "Enter Your Fibonacci Term No: " << endl;
    cin >> term;
    for(int i=0; i<term; i++){ //making every index value of -1
        fArr[i]=-1;
    }
    cout << "The Result Of Fibonacci Serise is: " << Fibo(term) << endl;

    return 0;
}

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Tags: c++ fibonacci fi

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Contributed on Feb 06 2023

isuro

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Fibonacci without recursion

Comment

# Non-recursive solution
def fibonacci2(n):
    if n == 0:
        return 0
    elif n == 1:
        return 1
    else:
        # Initialize the first two Fibonacci numbers
        a, b = 0, 1
        # Loop from 2 to n
        for _ in range(2, n + 1):
            # Compute the next Fibonacci number
            a, b = b, a + b
        return b

# Test the function
print(fibonacci2(5))

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Source: chat.openai.com

Tags: fibonacci python recursion rec

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Contributed on Sep 07 2023

Ben Akram

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fibonacci using recursion

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