orderby c# randomize

Repulsive Ray answered on July 26, 2020 Popularity 4/10 Helpfulness 1/10

answer orderby c# randomize

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orderby c# randomize

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public static IEnumerable<T> Shuffle<T>(this IEnumerable<T> source, Random rng)
{
    T[] elements = source.ToArray();
    // Note i > 0 to avoid final pointless iteration
    for (int i = elements.Length-1; i > 0; i--)
    {
        // Swap element "i" with a random earlier element it (or itself)
        int swapIndex = rng.Next(i + 1);
        T tmp = elements[i];
        elements[i] = elements[swapIndex];
        elements[swapIndex] = tmp;
    }
    // Lazily yield (avoiding aliasing issues etc)
    foreach (T element in elements)
    {
        yield return element;
    }
}

Popularity 4/10 Helpfulness 1/10 Language csharp

Source: devarama.com

Tags: c#

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Contributed on Mar 24 2022

Repulsive Ray

0 Answers Avg Quality 2/10

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orderby c# randomize

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var r = new Random();
var shuffled = ordered.OrderBy(x => r.Next());

Popularity 6/10 Helpfulness 10/10 Language csharp

Source: stackoverflow.com

Tags: c#

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Contributed on Feb 15 2021

Quaint Quetzal

0 Answers Avg Quality 2/10

c# shuffle

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private static Random rng = new Random();  

public static void Shuffle<T>(this IList<T> list)  
{  
    int n = list.Count;  
    while (n > 1) {  
        n--;  
        int k = rng.Next(n + 1);  
        T value = list[k];  
        list[k] = list[n];  
        list[n] = value;  
    }  
}

Popularity 9/10 Helpfulness 5/10 Language csharp

Source: stackoverflow.com

Tags: shuffle c# s

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Contributed on Jul 26 2020

Wicked Whale

0 Answers Avg Quality 2/10

C# Shuffle

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void ShuffleArray(int[] array)
{
  for (int i = 0; i < array.Length; i++)
  {
    int temp = array[i];
    int randomIndex = Random.Range(i, array.Length);
    array[i] = array[randomIndex];
    array[randomIndex] = temp;
  }
}

Popularity 6/10 Helpfulness 1/10 Language csharp

Source: Grepper

Tags: c# shuffle

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Contributed on Jan 14 2023

vexeval

0 Answers Avg Quality 2/10

orderby c# randomize

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