generate consecutive numbers at compile time

Quaint Quail answered on March 10, 2022 Popularity 1/10 Helpfulness 1/10

answer generate consecutive numbers at compile time

related generate consecutive numbers at compile time

generate consecutive numbers at compile time

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template<size_t n>
struct Elem{
    enum { res = 1 + Elem<n - 1>::res };
};

template<>
struct Elem<0> {
    enum { res = 0 };
};
template <size_t n, size_t...args>
struct A {
    static constexpr auto& array =
        A<n - 1, Elem<n>::res, args...>::array;
};
template <size_t...args>
struct A<0, args...> {
    static constexpr int array[] = { 0, args... };
};

template <size_t n>
static constexpr auto& Array = A<n>::array;

//пример использования
int main()
{   
    constexpr unsigned N = 8;
    for (unsigned n : Array<N>)
        cout << n << ' ';
    //0 1 2 3 4 5 6 7 8
}

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: ru.stackoverflow.com

Tags: c++ compile-time generate numbers

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Contributed on Mar 10 2022

Quaint Quail

0 Answers Avg Quality 2/10

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generate consecutive numbers at compile time

Comment

template<size_t n>
struct Elem{
    enum { res = 1 + Elem<n - 1>::res };
};

template<>
struct Elem<0> {
    enum { res = 0 };
};
template <size_t n, size_t...args>
struct A {
    static constexpr auto& array =
        A<n - 1, Elem<n>::res, args...>::array;
};
template <size_t...args>
struct A<0, args...> {
    static constexpr int array[] = { 0, args... };
};

template <size_t n>
static constexpr auto& Array = A<n>::array;

//пример использования
int main()
{   
    constexpr unsigned N = 8;
    for (unsigned n : Array<N>)
        cout << n << ' ';
    //0 1 2 3 4 5 6 7 8
}

Popularity 1/10 Helpfulness 1/10 Language cpp

Source: ru.stackoverflow.com

Tags: compile-time generate c++ numbers

Link to this answer
Share Copy Link

Contributed on Mar 10 2022

Quaint Quail

0 Answers Avg Quality 2/10

generate consecutive numbers at compile time

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generate consecutive numbers at compile time

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generate consecutive numbers at compile time

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