//Other Mathod using Foreach and includes

let chars = ['A', 'B', 'A', 'C', 'B'];

​

let uniqueChars = [];

chars.forEach((c) => {

    if (!uniqueChars.includes(c)) {

        uniqueChars.push(c);

    }

});

​

console.log(uniqueChars);

const names = ['John', 'Paul', 'George', 'Ringo', 'John'];

​

let unique = [...new Set(names)];

console.log(unique); // 'John', 'Paul', 'George', 'Ringo'

let arr = [1,2,3,1,1,1,4,5]

let filtered = arr.filter((item,index) => arr.indexOf(item) === index)

 console.log(filtered) // [1,2,3,4,5]

// how to remove duplicates from array in javascript

// 1. filter()

let num = [1, 2, 3, 3, 4, 4, 5, 5, 6];

let filtered = num.filter((a, b) => num.indexOf(a) === b)

console.log(filtered);

// Result: [ 1, 2, 3, 4, 5, 6 ]

​

// 2. Set()

const removeDuplicates = (arr) => [...new Set(arr)];

console.log(removeDuplicates([1, 2, 3, 3, 4, 4, 5, 5, 6]));

// Result: [ 1, 2, 3, 4, 5, 6 ]

uniqueArray = a.filter(function(item, pos) {

    return a.indexOf(item) == pos; 

})

​

const array = [1, 1, 2, 3, 5, 5, 1]

const uniqueArray = [...new Set(array)];

​

console.log(uniqueArray); // Output: [1, 2, 3, 5]

​

uniqueArray = a.filter(function(item, pos) {

    return a.indexOf(item) == pos;

})

​

const names = ['John', 'Paul', 'George', 'Ringo', 'John'];

​

function removeDups(names) {

  let unique = {};

  names.forEach(function(i) {

    if(!unique[i]) {

      unique[i] = true;

    }

  });

  return Object.keys(unique);

}

​

removeDups(names); // // 'John', 'Paul', 'George', 'Ringo'

let chars = ['A', 'B', 'A', 'C', 'B'];

let uniqueChars = [...new Set(chars)];

​

console.log(uniqueChars);

[...new Set(['1','1','2','2','3','3'])]

//this will return a new array with the unique primitive values

//I guess doing this with objects will require implementing equality method.