public static void printNumberOfArguments(int... numbers) {

    System.out.println(numbers.length);

}

printNumberOfArguments(1);

printNumberOfArguments(1, 2);

printNumberOfArguments(1, 2, 3);

printNumberOfArguments(new int[] { }); // no arguments here

printNumberOfArguments(new int[] { 1, 2 });

public class SomeClass{

    public void someMethod(int ... vars){

    // logic

}

}

​

var obj1 = new SomeClass();

var obj2 = new SomeClass();

​

obj1.someMethod(10, 20, 30, 40); // Works

obj2.someMethod(new int [] {10, 20, 30, 40}); // works

varargs:

It's possible to pass an arbitrary number of the same type arguments to 

a method using the special syntax named varargs (variable-length arguments).

 (Varargs can be used when we are unsure about the number of 

 arguments to be passed in a method)

Use varargs for any method (or constructor) that needs an array of

T (whatever type T may be) as input

One good example is String.format.

The format string can accept any number of parameters.

​