const ascending: any= values.sort((a,b) =>  (a > b ? 1 : -1));

const descending: any= values.sort((a,b) => (a > b ? -1 : 1))

const numbers = [4, 7, 1, 3, 6, 9, 2, 5];

const numbersSort = numbers.sort();

console.log(numbersSort);

//Output:[1, 2, 3, 4, 5, 6, 7, 9]

//ascending order

let ArrayOne = [1,32,5341,10,32,10,90]

ArrayOne = ArrayOne.sort(function(x,y){x-y})

//descending order

let ArrayTwo = [321,51,51,324,111,1000]

ArrayTwo = ArrayTwo.sort(function(x,y){y-x})

var fruits = ["Banana", "Orange", "Apple", "Mango"];

fruits.sort();        // Sorts the elements of fruits

var l = ["a", "w", "r", "e", "d", "c", "e", "f", "g"];

console.log(l.sort())

/*[ 'a', 'c', 'd', 'e', 'e', 'f', 'g', 'r', 'w' ]*/

How does the following code sort this array to be in numerical order?     

​

    var array=[25, 8, 7, 41]

​

    array.sort(function(a,b){

      return a - b

    })

​

I know that if the result of the computation is... 

​

**Less than 0**: "a" is sorted to be a lower index than "b".<br />

**Zero:** "a" and "b" are considered equal, and no sorting is performed.<br />

**Greater than 0:** "b" is sorted to be a lower index than "a".<br />

​

Is the array sort callback function called many times during the course of the sort?

​

If so, I'd like to know which two numbers are passed into the function each time. I assumed it first took "25"(a) and "8"(b), followed by "7"(a) and "41"(b), so:

​

25(a) - 8(b) = 17 (greater than zero, so sort "b" to be a lower index than "a"): 8, 25

​

7(a) - 41(b) = -34 (less than zero, so sort "a" to be a lower index than "b": 7, 41

​

How are the two sets of numbers then sorted in relation to one another?

​

Please help a struggling newbie!

​

​

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arr.sort((a, b) => a - b);

sorting an array