how to catch stop itteration in generator as None

Powerful Pelican answered on December 29, 2021 Popularity 1/10 Helpfulness 1/10

answer how to catch stop itteration in generator as None

how to catch stop itteration in generator as None

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# creating the list
L = [1,2,3,4,5,6]
# defining the generator
def generator(l):
    for i in l: yield i
    while True: yield  None
        

g = generator(L)

print(next(g)) # 1
print(next(g)) # 2
print(next(g)) # 3
print(next(g)) # 4
print(next(g)) # 5
print(next(g)) # 6
print(next(g)) # None
print(next(g)) # None
print(next(g)) # None

Popularity 1/10 Helpfulness 1/10 Language python

Source: Grepper

Tags: generator python

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Contributed on Dec 29 2021

Powerful Pelican

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