xxxxxxxxxx
#To replace the first occurrence of a pattern with a given string,
#use ${parameter/pattern/string}:
#!/bin/bash
firstString="I love Suzi and Marry"
secondString="Sara"
echo "${firstString/Suzi/$secondString}"
# prints 'I love Sara and Marry'
#To replace all occurrences, use ${parameter//pattern/string}:
message='The secret code is 12345'
echo "${message//[0-9]/X}"
# prints 'The secret code is XXXXX'
#(This is documented in the Bash Reference Manual, §3.5.3 "Shell Parameter Expansion".)
xxxxxxxxxx
#!/bin/bash
firstString="I love Suzi and Marry"
secondString="Sara"
echo "${firstString/Suzi/$secondString}"
# prints 'I love Sara and Marry'
xxxxxxxxxx
string="x + x + y = 3y"
echo $string | sed 's/x/y/g'
# Result: y + y + y = 3y
# Breakdown:
# Pass echo result ("pipe") into sed which substitudes x with y.
# Sed Usage: sed '<option: substitute>/<delimeter>/<replacement>/<scale: global>
xxxxxxxxxx
#1) Open the file in vi or vim
#2) Run the replacement command in vi (or vim) as follows
# Replace all matching patterns
:s%/PatternToReplace/Replacement
# Replace one matching pattern at a time
:s/PatternToReplace/Replacement