u = set.intersection(*setlist)

def intersection(lst1, lst2): 

    lst3 = [value for value in lst1 if value in lst2] 

    return lst3 

# Driver Code 

lst1 = [4, 9, 1, 17, 11, 26, 28, 54, 69] 

lst2 = [9, 9, 74, 21, 45, 11, 63, 28, 26] 

print(intersection(lst1, lst2)) 

list1 = [1, 2, 3, 4, 5]

list2 = [4, 5, 6, 7, 8]

​

intersection = list(set(list1) & set(list2))

print(intersection)

firstSet = {2, 3, 4, 5}

​

secondSet = {1, 3, 5, 7}

​

print(firstSet & secondSet)

# {3, 5}

# Python program to illustrate the intersection

# of two lists using set() method

def intersection(lst1, lst2):

    return list(set(lst1) & set(lst2))

# Driver Code

lst1 = [15, 9, 10, 56, 23, 78, 5, 4, 9]

lst2 = [9, 4, 5, 36, 47, 26, 10, 45, 87]

print(intersection(lst1, lst2))