python sort dictionary by key

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Trained Tuna answered on March 25, 2020 Popularity 10/10 Helpfulness 2/10

answer python sort dictionary by key

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python sort dictionary by key

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def sort_dict(dictionary, rev = True):
    l = list(dictionary.items())
    l.sort(reverse = rev)
    a = [item[1] for item in l]    
    z = ''    
    for x in a:
        z = z + str(x)
    return(z)

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Contributed on Jul 22 2021

Trained Tuna

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sort list of dictionaries by key python

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newlist = sorted(list_to_be_sorted, key=lambda k: k['name'])

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Contributed on Mar 25 2020

Stupid Stork

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dictionary sort python

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d={
  3: 4,
  1: 1,
  0: 0,
  4: 3,
  2: 1
}
y=dict(sorted(d.items(), key=lambda item: item[1]))
print(y) # {0: 0, 2: 1, 1: 2, 4: 3, 3: 4}

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Contributed on Jul 17 2022

Impossible Ibis

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python sort dict by keys

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# Your dictionary
your_dict = {'banana': 3, 'apple': 1, 'orange': 2}

# Sorting by keys
sorted_dict = dict(sorted(your_dict.items()))

# Displaying the sorted dictionary
print(sorted_dict)

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Contributed on Jan 21 2024

Testy Turtle

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sort dictionary python

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l = {1: 40, 2: 60, 3: 50, 4: 30, 5: 20}
d1 = dict(sorted(l.items(),key=lambda x:x[1],reverse=True))
print(d1) #output : {2: 60, 3: 50, 1: 40, 4: 30, 5: 20}
d2 = dict(sorted(l.items(),key=lambda x:x[1],reverse=False))
print(d2) #output : {5: 20, 4: 30, 1: 40, 3: 50, 2: 60}

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Contributed on Sep 10 2021

Rajanit Navapara

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python dict order a dict by key

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d1 = dict(sorted(d.items(), key = lambda x:x[0]))

Popularity 10/10 Helpfulness 6/10 Language python

Source: stackoverflow.com

Tags: key

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Contributed on Oct 20 2021

Dull Donkey

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sort dictionary

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#for dictionary d
sorted(d.items(), key=lambda x: x[1]) #for inceasing order
sorted(d.items(), key=lambda x: x[1], reverse=True) # for decreasing order
#it will return list of key value pair tuples

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Contributed on May 23 2020

Annoying Anteater

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sort the dictionary in python

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d = {2: 3, 1: 89, 4: 5, 3: 0}
od = sorted(d.items())
print(od)

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Contributed on Jul 18 2020

Clean Cicada

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python sort dict by key

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A={1:2, -1:4, 4:-20}
{k:A[k] for k in sorted(A)}

output:
{-1: 4, 1: 2, 4: -20}

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Contributed on Oct 15 2020

IJustWannaHelp

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how to sort a dictionary py

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orders = {
	'cappuccino': 54,
	'latte': 56,
	'espresso': 72,
	'americano': 48,
	'cortado': 41
}

sort_orders = sorted(orders.items(), key=lambda x: x[1], reverse=True)

for i in sort_orders:
	print(i[0], i[1])

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Contributed on May 18 2021

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python sort dictionary by key

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In [1]: import collections

In [2]: d = {2:3, 1:89, 4:5, 3:0}

In [3]: od = collections.OrderedDict(sorted(d.items()))

In [4]: od
Out[4]: OrderedDict([(1, 89), (2, 3), (3, 0), (4, 5)])

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Contributed on Apr 03 2020

Vivacious Vole

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python sort dictionary by key

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