js reduce

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20

// syntax: array.reduce(function, accumulator-initial-value)
let array = [3, 7, 2, 9, 5]
const result = array.reduce((accumulator, currentValue, currentIndex, arr) => {
  // code
}, initialValue)

// accumulator = will store return value of the function
// currentValue = iterate through each array element
// currentIndex = index of currentValue
// arr = original array
// initialValue = set accumulator initial value

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Source: developer.mozilla.org

Tags: javascript reduce

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Contributed on Jul 21 2021

Suman Majhi

0 Answers Avg Quality 2/10

javascript reduce

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185

var array = [36, 25, 6, 15];

array.reduce(function(accumulator, currentValue) {
  return accumulator + currentValue;
}, 0); // 36 + 25 + 6 + 15 = 82

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Tags: javascript j

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Contributed on May 21 2020

TC5550

0 Answers Avg Quality 2/10

JavaScript Reduce

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4

const arr = [1, 2, 3]
const result = arr.reduce((acc, curr) => acc + curr, 0)
// 1 + 2 + 3 = 6
console.log(result)

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Tags: javascript j

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Contributed on Dec 21 2022

Jozvan

0 Answers Avg Quality 2/10

reduce javascript

Comment

5

let array = [36, 25, 6, 15];
 
array.reduce((acc, curr) => acc + curr, 0)
// 36 + 25 + 6 + 15 = 82

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Tags: javascript j

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Contributed on Jul 05 2022

Rick Oburu

0 Answers Avg Quality 2/10

reduce javascript

Comment

9

var depthArray = [1, 2, [3, 4], 5, 6, [7, 8, 9]];

depthArray.reduce(function(flatOutput, depthItem) {
    return flatOutput.concat(depthItem);
}, []);

=> [1, 2, 3, 4, 5, 6, 7, 8, 9];


// --------------
const prices = [100, 200, 300, 400, 500];
const total = prices.reduce((total, cur) => {return total + cur} )
//  init value = 0 => total = 1500;


// --------------
const prices = [100, 200, 300, 400, 500];
const total = prices.reduce(function (total, cur) => {
                   return total + cur
                }, 1 )
// init value = 1 => so when plus all numnber will be result => 1501;

// --------------
const prices = [100, 200, 300, 400, 500];
const total = prices.reduce((total, cur) => total + cur )
// 1500;

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Contributed on Mar 03 2022

Zidane (Vi Ly - VietNam)

0 Answers Avg Quality 2/10

reduce in js

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0

Reduce in js

let arr=[5,6,2];
let sum=arr.reduce((accumulator,current,index,arr)=>{
   return accumulator+=current;
});
console.log(sum);//5+6+13

accumulator acumulate(hold) the sum output

reduce methood creat a new array and does not change actual array

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Contributed on May 19 2023

pabel reja

0 Answers Avg Quality 2/10

javascript reduce

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4

const sum = array.reduce((accumulator, element) => {
  return accumulator + element;
}, 0);

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Tags: javascript j

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Contributed on Apr 11 2021

Cooperative Capybara

0 Answers Avg Quality 2/10

js reduce

Comment

3

Sum array elements:
let myArr = [1,2,3,-1,-34,0]
return myArr.reduce((a,b) => a + b,0)

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Contributed on Dec 27 2020

Encouraging Earthworm

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js array reduce

Comment

3

// Arrow function
reduce((previousValue, currentValue) => { /* ... */ } )
reduce((previousValue, currentValue, currentIndex) => { /* ... */ } )
reduce((previousValue, currentValue, currentIndex, array) => { /* ... */ } )
reduce((previousValue, currentValue, currentIndex, array) => { /* ... */ }, initialValue)

// Callback function
reduce(callbackFn)
reduce(callbackFn, initialValue)

// Inline callback function
reduce(function(previousValue, currentValue) { /* ... */ })
reduce(function(previousValue, currentValue, currentIndex) { /* ... */ })
reduce(function(previousValue, currentValue, currentIndex, array) { /* ... */ })
reduce(function(previousValue, currentValue, currentIndex, array) { /* ... */ }, initialValue)

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Source: developer.mozilla.org

Tags: array-reduce array-redu

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Contributed on Feb 21 2022

Tung

0 Answers Avg Quality 2/10

javascript reduce

Comment

5

[3, 2.1, 5, 8].reduce((total, number) => total + number, 0)

// loop 1: 0 + 3
// loop 2: 3 + 2.1
// loop 3: 5.1 + 5
// loop 4: 10.1 + 8
// returns 18.1

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Source: dev.to

Tags: javascript j

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Contributed on Aug 10 2021

Troubled Tiger

0 Answers Avg Quality 2/10

js reduce

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