golang parse jason

Sparkling Skunk answered on April 17, 2021 Popularity 10/10 Helpfulness 5/10

answer golang parse jason

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golang parse jason

Comment

import "encoding/json"
//...

// ... 
myJsonString := `{"some":"json"}`

// `&myStoredVariable` is the address of the variable we want to store our
// parsed data in
json.Unmarshal([]byte(myJsonString), &myStoredVariable)
//...

Popularity 10/10 Helpfulness 5/10 Language javascript

Source: www.sohamkamani.com

Tags: javascript

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Contributed on Jun 08 2021

Sparkling Skunk

0 Answers Avg Quality 2/10

Closely Related Answers

parsing json data object in golang example

Comment

package main

import (
	"encoding/json"
	"fmt"
)

func main() {
	//Simple Employee JSON object which we will parse
	empJson := `{
		"id": 11,
		"name": "Irshad",
		"department": "IT",
		"designation": "Product Manager",
		"address": {
			"city": "Mumbai",
			"state": "Maharashtra",
			"country": "India"
		}
	}`

	// Declared an empty interface
	var result map[string]interface{}

	// Unmarshal or Decode the JSON to the interface.
	json.Unmarshal([]byte(empJson), &result)

	address := result["address"].(map[string]interface{})

	//Reading each value by its key
	fmt.Println("Id :", result["id"],
		"\nName :", result["name"],
		"\nDepartment :", result["department"],
		"\nDesignation :", result["designation"],
		"\nAddress :", address["city"], address["state"], address["country"])
}

Popularity 9/10 Helpfulness 7/10 Language go

Source: Grepper

Tags: go g

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Contributed on Apr 17 2021

Restu Wahyu Saputra

0 Answers Avg Quality 2/10

golang parse json file

Comment

// You need a struct to unmarshal file:
// After running this function with Some_struct, 
// your object will be filled with json file data
func parseJsonFile(file string, obj *Some_struct) {
	jsonFile, err := os.Open(file)
	// if we os.Open returns an error then handle it
	if err != nil {
		fmt.Println(err, "| Can find a file")
	} else {
		fmt.Println("File found!")
	}

	// defer the closing of our jsonFile so that we can parse it later on
	defer jsonFile.Close()

	// read our opened xmlFile as a byte array.
	byteValue, _ := ioutil.ReadAll(jsonFile)

	// we unmarshal our byteArray which contains our
	// jsonFile's content into 'users' which we defined above
	json.Unmarshal(byteValue, &obj)
}

Popularity 9/10 Helpfulness 4/10 Language go

Source: Grepper

Tags: file

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Contributed on Aug 11 2022

MaestroError

0 Answers Avg Quality 2/10

how to parse json response golang

Comment

package main

import (
   "encoding/json"
   "fmt"
)

type User struct {
   Username string `json:"username"`
   Age      int    `json:"age"`
}

func main() {

   var user User

   jsonString := `{"username": "john", "age": 25}`

   err := json.Unmarshal([]byte(jsonString), &user)

   if err != nil {
      panic(err)
   }

   // Output: john
   fmt.Println(user.Username)
   // Output: 25
   fmt.Println(user.Age)
}

Popularity 1/10 Helpfulness 1/10 Language go

Source: devhubby.com

Tags: go json response

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Contributed on Oct 13 2022

Ekaterina Budoragina

0 Answers Avg Quality 2/10

golang parse jason

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