URLSearchParams(new URL(url).search)

Horrible Hyena answered on April 5, 2021 Popularity 10/10 Helpfulness 5/10

answer URLSearchParams(new URL(url).search)

URLSearchParams(new URL(url).search)

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Tip Horrible Hyena 1 GREPCC

// Retrieve params via url.search, passed into ctor
var url = new URL('https://example.com?foo=1&bar=2');
var params = new URLSearchParams(url.search);

// Pass in a string literal
var params2 = new URLSearchParams("foo=1&bar=2");
var params2a = new URLSearchParams("?foo=1&bar=2");

// Pass in a sequence of pairs
var params3 = new URLSearchParams([["foo", "1"], ["bar", "2"]]);

// Pass in a record
var params4 = new URLSearchParams({"foo": "1", "bar": "2"});

xxxxxxxxxx

// Retrieve params via url.search, passed into ctor

var url = new URL('https://example.com?foo=1&bar=2');

var params = new URLSearchParams(url.search);

// Pass in a string literal

var params2 = new URLSearchParams("foo=1&bar=2");

var params2a = new URLSearchParams("?foo=1&bar=2");

// Pass in a sequence of pairs

var params3 = new URLSearchParams([["foo", "1"], ["bar", "2"]]);

// Pass in a record

var params4 = new URLSearchParams({"foo": "1", "bar": "2"});

Popularity 10/10 Helpfulness 5/10 Language javascript

Source: developer.mozilla.org

Tags: javascript

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Contributed on Apr 05 2021

Horrible Hyena

0 Answers Avg Quality 2/10

URLSearchParams(new URL(url).search)

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