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for (int x = 0; x < YourArray.GetLength(0); x++)
{
for (int y = 0; y < YourArray.GetLength(1); y++)
{
Console.WriteLine(YourArray[x, y]);
}
}
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If you want to iterate over every item in the array as if it were a flattened array, you can just do:
foreach (int i in array) {
Console.Write(i);
}
which would print 123456
If you want to be able to know the x and y indexes as well, you'll need to do:
for (int x = 0; x < array.GetLength(0); x += 1) {
for (int y = 0; y < array.GetLength(1); y += 1) {
Console.Write(array[x, y]);
}
}
Alternatively you could use a jagged array instead (an array of arrays):
int[][] array = new int[2][] { new int[3] {1, 2, 3}, new int[3] {4, 5, 6} };
foreach (int[] subArray in array) {
foreach (int i in subArray) {
Console.Write(i);
}
}
or
int[][] array = new int[2][] { new int[3] {1, 2, 3}, new int[3] {4, 5, 6} };
for (int j = 0; j < array.Length; j += 1) {
for (int k = 0; k < array[j].Length; k += 1) {
Console.Write(array[j][k]);
}
}
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static IEnumerable<KeyValuePair<T, U>> Zip<T, U>(IEnumerable<T> first, IEnumerable<U> second)
{
IEnumerator<T> firstEnumerator = first.GetEnumerator();
IEnumerator<U> secondEnumerator = second.GetEnumerator();
while (firstEnumerator.MoveNext())
{
if (secondEnumerator.MoveNext())
{
yield return new KeyValuePair<T, U>(firstEnumerator.Current, secondEnumerator.Current);
}
else
{
yield return new KeyValuePair<T, U>(firstEnumerator.Current, default(U));
}
}
while (secondEnumerator.MoveNext())
{
yield return new KeyValuePair<T, U>(default(T), secondEnumerator.Current);
}
}
static void Test()
{
IList<string> names = new string[] { "one", "two", "three" };
IList<int> ids = new int[] { 1, 2, 3, 4 };
foreach (KeyValuePair<string, int> keyValuePair in ParallelEnumerate(names, ids))
{
Console.WriteLine(keyValuePair.Key ?? "<null>" + " - " + keyValuePair.Value.ToString());
}
}
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class ArrayClass2D
{
static void Print2DArray(int[,] arr)
{
// Display the array elements.
for (int i = 0; i < arr.GetLength(0); i++)
{
for (int j = 0; j < arr.GetLength(1); j++)
{
System.Console.WriteLine("Element({0},{1})={2}", i, j, arr[i, j]);
}
}
}
static void Main()
{
// Pass the array as an argument.
Print2DArray(new int[,] { { 1, 2 }, { 3, 4 }, { 5, 6 }, { 7, 8 } });
// Keep the console window open in debug mode.
System.Console.WriteLine("Press any key to exit.");
System.Console.ReadKey();
}
}
/* Output:
Element(0,0)=1
Element(0,1)=2
Element(1,0)=3
Element(1,1)=4
Element(2,0)=5
Element(2,1)=6
Element(3,0)=7
Element(3,1)=8
*/