asyncio.run() cannot be called from a running event loop from jupyterlab

Cruel Chipmunk answered on September 19, 2020 Popularity 10/10 Helpfulness 2/10

answer asyncio.run() cannot be called from a running event loop from jupyterlab

asyncio.run() cannot be called from a running event loop from jupyterlab

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Tip Cruel Chipmunk 1 GREPCC

import asyncio
def wait_for_change(widget, value):
    future = asyncio.Future()
    def getvalue(change):
        # make the new value available
        future.set_result(change.new)
        widget.unobserve(getvalue, value)
    widget.observe(getvalue, value)
    return future

xxxxxxxxxx

import asyncio

def wait_for_change(widget, value):

    future = asyncio.Future()

    def getvalue(change):

        # make the new value available

        future.set_result(change.new)

        widget.unobserve(getvalue, value)

    widget.observe(getvalue, value)

    return future

Popularity 10/10 Helpfulness 2/10 Language python

Source: ipywidgets.readthedocs.io

Tags: event-loop jupyter-lab python

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Contributed on Sep 19 2020

Cruel Chipmunk

0 Answers Avg Quality 2/10

asyncio.run() cannot be called from a running event loop from jupyterlab

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